Егор6 лет назад
1/( x-1) 2 + 3/(x - 1) - 10=0;
(1 + 3(х - 1) - 10(х-1) 2 )/(х - 1) 2 = 0;
(1 + 3х - 3 - 10(х 2 + 1 - 2х))/(х - 1) 2 = 0;
-2 + 3х - 10х 2 - 10 + 20х = 0;
(х - 1) 2 ≠0 ⇒ х ≠ 1.
-10х 2 + 23х - 12 = 0;
10х 2 - 23х + 12 = 0;
Д = 529 + 4 * 12 * 10 = 529 - 480 = 49;
х1 = (23 + 7)/20 = 30/20 = 1,5;
х2 = (23 - 7)/20 = 16/20 = 4/5 = 0,8.