Решите уравнение срочно 1)(2x-1)(4x^2+2x+q11)=23+4x(2x^2-3) 2) 16x(4x^2-5)+17=(4x-1)(16x^2-4x+1)

1 )( 2 * x - 1) * (4 * x ^ 2 + 2 * x + 11 ) = 23 + 4 * x * ( 2 * x ^ 2 - 3 ) ; 8 * x ^ 3 + 4 * x ^ 2 + 22 * x - 4 * x ^ 2 - 2 * x - 11 = 23 + 8 * x ^ 3 - 12 * x ; 8 * x ^ 3 + 4 * x ^ 2 + 22 * x - 4 * x ^ 2 - 2 * x - 11 - 23 - 8 * x ^ 3 + 12 * x = 0 ; + 22 * x - 2 * x - 11 - 23 + 12 * x = 0 ; + 32 * x -34 = 0 ; 32 * x = 34 ; x = 34 / 32 ; x = 17 / 16 . 2 ) 16 * x * ( 4 * x ^ 2 - 5 ) + 17 = ( 4 * x - 1 ) * ( 16 * x ^ 2 - 4 * x + 1 ) ; 64 * x ^ 3 - 80 * x + 17 = 64 * x ^ 3 - 16 * x ^ 2 + 4 * x - 16 * x ^ 2 + 4 * x - 1 ; - 80 * x + 17 = - 32 * x ^ 2 + 8 * x - 1 ; - 80 * x + 17 + 32 * x ^ 2 - 8 * x + 1 = 0 ; + 32 * x ^ 2 - 88 * x + 18 = 0 ; D = b ^2 - 4ac = (-88) ^ 2 - 4·32·18 = 7744 - 2304 = 5440; x1 = (88 - √5440 ) /(2·32) = 1.375 - 0.125√85; x2 = (88 + √5440 )/(2·32 ) = 1.375 + 0.125√85 .